Least significant difference (LSD) method MCQs With Answer

Least significant difference (LSD) method MCQs With Answer provides B. Pharm students a focused review of the LSD post-hoc test used after ANOVA for pairwise comparisons. This introduction covers key concepts such as pooled error variance, MSE, t-critical values, significance level (alpha), protection by overall F-test, and practical applications in pharmacology, bioassay, formulation studies and experimental design. Understanding assumptions, limitations (inflated Type I error), calculation formula and interpretation of results prepares students for data analysis in drug research. These targeted MCQs reinforce theory, calculations, software output interpretation and decision-making for laboratory studies. Now let’s test your knowledge with 30 MCQs on this topic.

Q1. What is the primary purpose of the Least Significant Difference (LSD) method?

  • To test for normality of residuals
  • To perform pairwise comparisons after a significant ANOVA
  • To replace ANOVA for overall group differences
  • To estimate sample size for experiments

Correct Answer: To perform pairwise comparisons after a significant ANOVA

Q2. Which statistic is central to the LSD formula for pairwise mean comparisons?

  • Mean square between groups (MSB)
  • Mean square error (MSE)
  • Coefficient of variation (CV)
  • Standard error of the mean (SEM) only

Correct Answer: Mean square error (MSE)

Q3. The formula for LSD (two-sample equal n) commonly includes which of these components?

  • t-critical × sqrt(2 × MSE / n)
  • z-critical × sqrt(MSB / n)
  • F-critical × sqrt(MSE / 2n)
  • Chi-square × sqrt(MSE / n)

Correct Answer: t-critical × sqrt(2 × MSE / n)

Q4. When is it appropriate to apply Fisher’s LSD without adjustment?

  • Always, regardless of ANOVA outcome
  • Only after a significant overall F-test in ANOVA
  • Only for non-parametric data
  • When sample sizes vary widely

Correct Answer: Only after a significant overall F-test in ANOVA

Q5. Which assumption is NOT required for valid LSD comparisons?

  • Independence of observations
  • Homogeneity of variances across groups
  • Normality of residuals
  • Equal group means before testing

Correct Answer: Equal group means before testing

Q6. What is a main limitation of the LSD method in multiple comparisons?

  • It is overly conservative and misses true differences
  • It inflates Type I error rate when many comparisons are made
  • It requires extremely large sample sizes
  • It only works for two-group experiments

Correct Answer: It inflates Type I error rate when many comparisons are made

Q7. In a pharmacology bioassay with four treatments (n per group = 6), which degrees of freedom are used to find t-critical for LSD?

  • df = number of treatments – 1
  • df = total sample size – number of treatments
  • df = total sample size – 1
  • df = number of pairwise comparisons

Correct Answer: df = total sample size – number of treatments

Q8. What does “protected LSD” refer to?

  • Applying LSD only when overall ANOVA F-test is significant
  • Using LSD without checking assumptions
  • Using LSD with Bonferroni correction
  • Applying LSD before running ANOVA

Correct Answer: Applying LSD only when overall ANOVA F-test is significant

Q9. How does unequal sample size (n) between groups affect the LSD calculation?

  • It has no effect; formula is unchanged
  • The pooled variance is not estimable
  • The LSD uses sqrt(MSE × (1/n1 + 1/n2)) instead of 2/n
  • LSD cannot be computed for unequal n

Correct Answer: The LSD uses sqrt(MSE × (1/n1 + 1/n2)) instead of 2/n

Q10. Which post-hoc test is more conservative than LSD for controlling family-wise error?

  • Tukey’s HSD
  • Unprotected LSD
  • Pairwise t-tests without adjustment
  • No post-hoc test is more conservative

Correct Answer: Tukey’s HSD

Q11. In LSD, the t-critical value is taken from which distribution?

  • Chi-square distribution
  • t-distribution with pooled error df
  • F-distribution with (k-1, N-k) df
  • Normal distribution (z)

Correct Answer: t-distribution with pooled error df

Q12. If MSE = 4, n = 5 per group, and t-critical = 2.571, what is the LSD value for pairwise means?

  • 2.571 × sqrt(2 × 4 / 5) = 3.646
  • 2.571 × sqrt(4 / 5) = 2.304
  • 2.571 × sqrt(2 / 5) = 1.628
  • 2.571 × sqrt(8 / 5) = 3.646 (duplicate)

Correct Answer: 2.571 × sqrt(2 × 4 / 5) = 3.646

Q13. In B. Pharm research, a significant LSD difference between formulations indicates what?

  • The formulations are clinically equivalent
  • There is a statistically significant difference in the measured response
  • The experiment must be repeated due to Type II error
  • No conclusion can be drawn without Bonferroni correction

Correct Answer: There is a statistically significant difference in the measured response

Q14. Which software output element is essential to compute LSD manually?

  • Total sum of squares only
  • Mean square error (MSE) and error degrees of freedom
  • Group means only
  • R-squared value only

Correct Answer: Mean square error (MSE) and error degrees of freedom

Q15. When comparing many treatments, which strategy reduces the risk of inflated Type I error compared to unadjusted LSD?

  • Performing only the largest pairwise differences
  • Using more liberal alpha (e.g., 0.10)
  • Using more conservative post-hoc tests (Tukey, Bonferroni)
  • Reducing sample size

Correct Answer: Using more conservative post-hoc tests (Tukey, Bonferroni)

Q16. The LSD method assumes homogeneity of variances. Which test can check this assumption?

  • Shapiro-Wilk test
  • Levene’s test
  • Kaplan-Meier test
  • Cochran’s Q for paired data

Correct Answer: Levene’s test

Q17. If ANOVA F-test is not significant, what is the recommended action regarding LSD comparisons?

  • Proceed with LSD regardless
  • Avoid LSD pairwise tests as they are not protected
  • Increase alpha for LSD
  • Switch to non-parametric LSD

Correct Answer: Avoid LSD pairwise tests as they are not protected

Q18. For which experimental design is LSD applicable for pairwise comparisons?

  • Only completely randomized designs
  • Any design analyzed by ANOVA if assumptions met (CRD, RBD, factorial)
  • Only paired t-test designs
  • Only non-parametric designs

Correct Answer: Any design analyzed by ANOVA if assumptions met (CRD, RBD, factorial)

Q19. Which term describes the pooled estimate of within-group variability used in LSD?

  • Between-group variance
  • Mean square error (MSE)
  • Total variance
  • Group variance

Correct Answer: Mean square error (MSE)

Q20. In a bioassay comparing three dose levels, which pairwise result would be declared significant using LSD?

  • Difference between means = 0.5 when LSD = 0.8
  • Difference between means = 1.2 when LSD = 1.0
  • Difference between means = 0.9 when LSD = 1.0
  • Difference between means = 0.2 when LSD = 0.15

Correct Answer: Difference between means = 1.2 when LSD = 1.0

Q21. Which phrase best describes Fisher’s LSD compared to family-wise methods?

  • More conservative and reduces Type I error
  • Less conservative and more powerful but risks inflated Type I error
  • Identical in error control to Bonferroni
  • Not based on pooled variance

Correct Answer: Less conservative and more powerful but risks inflated Type I error

Q22. In reporting LSD results in a B. Pharm article, which information should be included?

  • MSE, df for error, t-critical, LSD value and which comparisons were significant
  • Only p-values without test statistics
  • Only raw means without error estimates
  • Only sample sizes without ANOVA details

Correct Answer: MSE, df for error, t-critical, LSD value and which comparisons were significant

Q23. If researchers apply LSD to exploratory data with many comparisons, what is a common recommendation?

  • Report results as confirmatory without caution
  • Use LSD and ignore family-wise error
  • Label conclusions as exploratory and consider adjustment or replication
  • Always prefer LSD over all other methods

Correct Answer: Label conclusions as exploratory and consider adjustment or replication

Q24. Which outcome from an ANOVA justifies conducting LSD tests?

  • Non-significant F with p > 0.05
  • Significant F with p < alpha
  • High R-squared value only
  • Significant Levene’s test

Correct Answer: Significant F with p < alpha

Q25. How does the number of treatments (k) affect the number of pairwise comparisons for LSD?

  • Number of comparisons = k
  • Number of comparisons = k – 1
  • Number of comparisons = k(k – 1)/2
  • Number of comparisons = 2^k

Correct Answer: Number of comparisons = k(k – 1)/2

Q26. In an ANOVA table, which value is directly used to compute MSE?

  • Error sum of squares divided by error df
  • Total sum of squares divided by total df
  • Between treatments sum of squares divided by treatments df
  • R-squared multiplied by variance

Correct Answer: Error sum of squares divided by error df

Q27. When comparing two means with unequal variances, the standard LSD is inappropriate. What is a remedy?

  • Ignore variance inequality and proceed
  • Use Welch’s t-test or adjust degrees of freedom for unequal variances
  • Always increase sample size to equalize variances
  • Use LSD with pooled variance regardless

Correct Answer: Use Welch’s t-test or adjust degrees of freedom for unequal variances

Q28. Which of the following best describes the role of LSD in factorial experiments?

  • LSD cannot be used in factorial experiments
  • LSD can compare main effect levels or interaction cell means after appropriate ANOVA
  • LSD replaces interaction terms in the model
  • LSD is used to test block effects only

Correct Answer: LSD can compare main effect levels or interaction cell means after appropriate ANOVA

Q29. If the pooled MSE decreases while other factors remain constant, what happens to the LSD value?

  • LSD increases
  • LSD decreases
  • LSD remains unchanged
  • LSD becomes infinite

Correct Answer: LSD decreases

Q30. Which interpretation is correct if a pairwise mean difference exceeds the LSD threshold?

  • The difference is statistically significant at the chosen alpha
  • The difference is not statistically significant
  • The F-test must be non-significant
  • No interpretation is possible without Bonferroni correction

Correct Answer: The difference is statistically significant at the chosen alpha

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