Principle of NMR Spectroscopy MCQs With Answer (M. Pharm)
Nuclear Magnetic Resonance (NMR) spectroscopy is a cornerstone of Modern Pharmaceutical Analytical Techniques, offering unparalleled insight into molecular structure, dynamics, and purity. This quiz focuses on the core principles of NMR—nuclear spin behavior in a magnetic field, Larmor precession, chemical shift, shielding/deshielding, scalar coupling, relaxation, FT acquisition, and practical parameters such as shimming, locking, and spectral width. Designed for M. Pharm students, these MCQs emphasize conceptual clarity and application-oriented understanding relevant to drug analysis, impurity profiling, and structural elucidation. Work through the questions to strengthen your grasp of NMR fundamentals and build a solid foundation for advanced 1D/2D experiments and quantitative NMR applications in pharmaceutical research.
Q1. Which statement best describes the fundamental principle of NMR spectroscopy?
- NMR detects transitions of electrons between spin states in an external electric field.
- NMR measures absorption of radiofrequency energy by nuclei with non-zero spin placed in a strong magnetic field at their Larmor frequency.
- NMR monitors vibrational transitions of nuclei driven by infrared light.
- NMR relies on scattering of X-rays by electron density.
Correct Answer: NMR measures absorption of radiofrequency energy by nuclei with non-zero spin placed in a strong magnetic field at their Larmor frequency.
Q2. What is the Larmor precession frequency (in Hz) of a nucleus in a magnetic field B0?
- ν0 = γ B0
- ν0 = (γ/2π) B0
- ν0 = γ B0 / (2π B1)
- ν0 = h γ B0
Correct Answer: ν0 = (γ/2π) B0
Q3. Why is tetramethylsilane (TMS) used as a chemical shift reference in 1H and 13C NMR?
- It has strongly deshielded protons that resonate downfield of most analytes.
- It gives a single, sharp, highly shielded signal and is chemically inert and volatile.
- It covalently binds to all analytes ensuring internal calibration.
- It contains no hydrogen or carbon and hence does not interfere.
Correct Answer: It gives a single, sharp, highly shielded signal and is chemically inert and volatile.
Q4. In NMR, chemical shift δ is reported in which unit and defined as?
- Hz; frequency difference divided by spectrometer frequency.
- ppm; (νsample − νref)/νspectrometer × 106.
- Tesla; proportional to B0.
- ppm; independent of reference compound.
Correct Answer: ppm; (νsample − νref)/νspectrometer × 106.
Q5. How does an electronegative substituent affect the chemical shift of nearby protons?
- Increases electron density, causing upfield shift (lower δ).
- Decreases shielding via −I effect, causing downfield shift (higher δ).
- Has no effect on chemical shift; only temperature matters.
- Only changes J-coupling constants, not δ.
Correct Answer: Decreases shielding via −I effect, causing downfield shift (higher δ).
Q6. Which statement about spin–spin coupling (J) is correct?
- J is measured in ppm and scales with B0.
- J is measured in Hz and is largely independent of B0.
- J only occurs between magnetically equivalent nuclei.
- J results from through-space dipolar interactions exclusively.
Correct Answer: J is measured in Hz and is largely independent of B0.
Q7. For a proton with n equivalent vicinal neighbors (no exchange, first-order), the observed multiplicity is:
- n
- 2n + 1
- n + 1
- 2n
Correct Answer: n + 1
Q8. In 1H NMR, the area under a resonance is proportional to:
- The gyromagnetic ratio of the observed nucleus.
- The number of chemically equivalent protons contributing to that signal.
- The magnetic field strength squared.
- The T2 relaxation time only.
Correct Answer: The number of chemically equivalent protons contributing to that signal.
Q9. Which pair correctly matches relaxation mechanisms with their descriptions?
- T1: transverse dephasing; T2: longitudinal recovery.
- T1: spin–lattice (longitudinal) relaxation; T2: spin–spin (transverse) dephasing.
- T1 and T2 are identical and field-independent.
- T1 governs linewidth; T2 governs NOE.
Correct Answer: T1: spin–lattice (longitudinal) relaxation; T2: spin–spin (transverse) dephasing.
Q10. The primary advantage of Fourier Transform (FT) NMR over continuous-wave (CW) NMR is:
- It eliminates the need for superconducting magnets.
- It permits pulsed excitation, time-domain acquisition (FID), signal averaging, and rapid multi-dimensional experiments for improved sensitivity.
- It increases chemical shift dispersion in ppm.
- It removes the need for sample spinning.
Correct Answer: It permits pulsed excitation, time-domain acquisition (FID), signal averaging, and rapid multi-dimensional experiments for improved sensitivity.
Q11. To prevent aliasing during FID digitization, the chosen spectral width (SW) must satisfy:
- SW < 2 × highest frequency component to reduce noise.
- SW ≥ 2 × the highest frequency offset from the carrier (Nyquist criterion).
- SW equals the reference frequency exactly.
- SW is irrelevant in FT-NMR.
Correct Answer: SW ≥ 2 × the highest frequency offset from the carrier (Nyquist criterion).
Q12. Which is true about 13C NMR of organic molecules?
- 13C has 100% natural abundance and is highly sensitive.
- Broadband 1H decoupling simplifies spectra by removing 1H–13C couplings and enhances signal via NOE.
- 13C chemical shifts are reported relative to DSS, not TMS.
- 13C spectra always show integrals proportional to carbon count.
Correct Answer: Broadband 1H decoupling simplifies spectra by removing 1H–13C couplings and enhances signal via NOE.
Q13. Regarding DEPT experiments in 13C NMR, which statement is correct?
- DEPT displays all carbons including quaternary with distinct phases.
- In DEPT-135, CH and CH3 appear positive, CH2 negative, and quaternary carbons are absent.
- DEPT distinguishes carbons based on chemical shift anisotropy only.
- DEPT signals are unaffected by proton decoupling.
Correct Answer: In DEPT-135, CH and CH3 appear positive, CH2 negative, and quaternary carbons are absent.
Q14. The Nuclear Overhauser Effect (NOE) primarily provides information on:
- Through-bond scalar couplings up to three bonds.
- Through-space proximity of nuclei within about 5 Å via dipolar cross-relaxation.
- Chemical exchange rates on the millisecond timescale only.
- Electron spin density at the nucleus.
Correct Answer: Through-space proximity of nuclei within about 5 Å via dipolar cross-relaxation.
Q15. What is the purpose of the field–frequency lock in solution NMR?
- To lock the sample tube position and prevent spinning.
- To use the deuterium signal of the solvent to stabilize spectrometer frequency and compensate for B0 drift.
- To suppress residual solvent protons via selective saturation.
- To increase the gyromagnetic ratio of detected nuclei.
Correct Answer: To use the deuterium signal of the solvent to stabilize spectrometer frequency and compensate for B0 drift.
Q16. Which statement about quadrupolar nuclei (I > 1/2) is correct?
- They typically have slow relaxation and very sharp lines in solution NMR.
- Their rapid quadrupolar relaxation often broadens or collapses couplings, leading to weak/broad signals (e.g., 14N).
- They cannot be observed by NMR.
- They always give resolved first-order multiplets.
Correct Answer: Their rapid quadrupolar relaxation often broadens or collapses couplings, leading to weak/broad signals (e.g., 14N).
Q17. Which parameter changes with magnetic field strength B0 while the others remain essentially constant?
- J-coupling constants (Hz)
- Chemical shift in ppm
- Chemical shift in Hz
- Multiplicity (pattern) from scalar coupling in first-order spectra
Correct Answer: Chemical shift in Hz
Q18. In protic compounds, rapid exchange of –OH or –NH protons usually leads to which observation in 1H NMR at room temperature?
- Strong, well-resolved coupling to neighboring CH protons.
- Broad singlets with suppressed scalar coupling and temperature/solvent dependence.
- Complete disappearance of all non-exchanging signals.
- Upfield shift due solely to ring current effects.
Correct Answer: Broad singlets with suppressed scalar coupling and temperature/solvent dependence.
Q19. For accurate quantitative 1H NMR integrations (qNMR), which acquisition condition is most critical?
- Use a relaxation delay (D1) ≥ 5 × the longest T1 of the nuclei being integrated.
- Apply strong continuous decoupling during acquisition.
- Use the narrowest possible spectral width for better resolution.
- Minimize number of scans to prevent saturation.
Correct Answer: Use a relaxation delay (D1) ≥ 5 × the longest T1 of the nuclei being integrated.
Q20. Which 2D experiment correlates directly bonded 1H and 13C nuclei (one-bond heteronuclear couplings)?
- COSY
- NOESY
- HSQC
- HMBC
Correct Answer: HSQC

I am a Registered Pharmacist under the Pharmacy Act, 1948, and the founder of PharmacyFreak.com. I hold a Bachelor of Pharmacy degree from Rungta College of Pharmaceutical Science and Research. With a strong academic foundation and practical knowledge, I am committed to providing accurate, easy-to-understand content to support pharmacy students and professionals. My aim is to make complex pharmaceutical concepts accessible and useful for real-world application.
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