Reaction kinetics – second order MCQs With Answer
Understanding reaction kinetics is essential for B.Pharm students involved in drug stability, formulation science and metabolic studies. These 30 MCQs focus on second-order reactions — bimolecular processes where the rate depends on the concentrations of two reactant molecules or on the square of one reactant. Topics include differential and integrated rate laws, half-life dependence on initial concentration, units of the rate constant (M⁻¹ s⁻¹), graphical analysis (1/[A] vs. t), pseudo-first-order conditions, and pharmaceutical applications such as degradation kinetics. Questions emphasize derivations, experiment interpretation and problem-solving to build laboratory and exam readiness. Now let’s test your knowledge with 30 MCQs on this topic.
Q1. Which integrated rate law corresponds to a second-order reaction of type 2A → products?
- ln[A] = -kt + ln[A]0
- 1/[A] – 1/[A]0 = kt
- [A] = [A]0 e^{-kt}
- [A] – [A]0 = -kt
Correct Answer: 1/[A] – 1/[A]0 = kt
Q2. What are the units of the rate constant k for a second-order reaction in concentration units of mol L⁻¹ and time in seconds?
- s⁻¹
- mol L⁻¹ s⁻¹
- L mol⁻¹ s⁻¹ (or M⁻¹ s⁻¹)
- mol² L⁻² s⁻¹
Correct Answer: L mol⁻¹ s⁻¹ (or M⁻¹ s⁻¹)
Q3. For a second-order reaction 2A → products, how does the half-life (t1/2) depend on the initial concentration [A]0?
- t1/2 is independent of [A]0
- t1/2 = ln 2 / (k [A]0)
- t1/2 = 1 / (k [A]0)
- t1/2 = [A]0 / k
Correct Answer: t1/2 = 1 / (k [A]0)
Q4. Which plot yields a straight line for a second-order reaction with respect to reactant A?
- ln[A] vs. t
- [A] vs. t
- 1/[A] vs. t
- ln(1/[A]) vs. t
Correct Answer: 1/[A] vs. t
Q5. If rate = k[A][B] and initially [A]0 = [B]0, what is the apparent rate law in terms of [A] only?
- rate = k[A]
- rate = k[A]²
- rate = k[A]^{1/2}
- rate = k
Correct Answer: rate = k[A]²
Q6. Which experimental observation supports that a reaction is second-order?
- Plot of ln[A] vs. t is linear
- Half-life is constant over different [A]0
- Plot of 1/[A] vs. t is linear with slope = k
- Rate is independent of concentration
Correct Answer: Plot of 1/[A] vs. t is linear with slope = k
Q7. In a bimolecular reaction A + B → products, under pseudo-first-order conditions when [B] >> [A], the observed rate constant kobs equals:
- k / [B]
- k [B]
- k [A]
- k
Correct Answer: k [B]
Q8. For a second-order reaction with rate = k[A]², what is the slope of the 1/[A] vs. t plot?
- -k
- k
- k/2
- -1/k
Correct Answer: k
Q9. Which statement best describes a molecularity of two in an elementary reaction step?
- Involves one molecule undergoing rearrangement
- Involves two reactant molecules colliding in a single step
- Occurs in two separate steps each unimolecular
- Always implies third-order kinetics experimentally
Correct Answer: Involves two reactant molecules colliding in a single step
Q10. How does temperature generally affect the second-order rate constant k?
- k decreases with increasing temperature
- k is independent of temperature
- k increases with temperature according to the Arrhenius equation
- k changes unpredictably and not described by Arrhenius
Correct Answer: k increases with temperature according to the Arrhenius equation
Q11. Given the second-order integrated rate law 1/[A] – 1/[A]0 = kt, what is [A] at time t?
- [A] = [A]0 e^{-kt}
- [A] = 1 / (1/[A]0 + kt)
- [A] = [A]0 – kt
- [A] = [A]0 / (1 + k t [A]0^{2})
Correct Answer: [A] = 1 / (1/[A]0 + kt)
Q12. For a reaction A + B → products with initial concentrations [A]0 ≠ [B]0, the integrated rate expression is:
- 1/[A] – 1/[A]0 = kt for all cases
- ln([B]/[A]) = k t ([B]0 – [A]0)
- More complex logarithmic form involving [A]0 and [B]0
- [A] = [A]0 e^{-kt}
Correct Answer: More complex logarithmic form involving [A]0 and [B]0
Q13. Which experimental technique is commonly used to follow concentration vs. time for kinetic analysis in pharmaceutical studies?
- Mass spectrometry without quantitation
- UV–visible spectroscopy monitoring absorbance changes
- X-ray crystallography
- Polarography only for solids
Correct Answer: UV–visible spectroscopy monitoring absorbance changes
Q14. When plotting kinetic data for a second-order reaction, the y-intercept of the 1/[A] vs. t plot equals:
- k
- 1/[A]0
- [A]0
- 0
Correct Answer: 1/[A]0
Q15. If two reactants follow rate = k[A][B] and initial rates doubling [A] while [B] constant quadruples the rate, what is the order with respect to A?
- Zero order in A
- First order in A
- Second order in A
- Fractional order in A
Correct Answer: First order in A
Q16. In enzymatic degradation approximated as second-order between drug and nucleophile, which approximation can simplify kinetics when nucleophile is in excess?
- Steady-state approximation
- Pseudo-first-order approximation
- Equilibrium approximation only
- Negligible rate approximation
Correct Answer: Pseudo-first-order approximation
Q17. Which quantity is directly obtained from the slope of 1/[A] vs. t for a 2A → products reaction?
- Activation energy
- Rate constant k
- Half-life t1/2
- Order of reaction only
Correct Answer: Rate constant k
Q18. For a second-order reaction, doubling the initial concentration [A]0 will change the half-life t1/2 how?
- t1/2 doubles
- t1/2 halves
- t1/2 remains unchanged
- t1/2 increases fourfold
Correct Answer: t1/2 halves
Q19. Which kinetic observation can distinguish between an elementary bimolecular step and a chain mechanism giving apparent second-order kinetics?
- Only rate law measurement at one concentration
- Temperature dependence and mechanistic probes (isotope effects, intermediate detection)
- Measuring pH alone
- Observing color change
Correct Answer: Temperature dependence and mechanistic probes (isotope effects, intermediate detection)
Q20. In a second-order degradation study of a drug, why is it important to report the units of k?
- Units are irrelevant for comparing rates
- Units indicate experimental error
- Units identify reaction order and allow comparison between studies
- Units determine the stoichiometry of products
Correct Answer: Units identify reaction order and allow comparison between studies
Q21. Which expression gives the time required for concentration to fall to one-quarter for a second-order reaction 2A → products?
- t = (3)/(k [A]0)
- t = (1)/(k [A]0)
- t = ln4 / (k [A]0)
- t = (1/4)/(k [A]0)
Correct Answer: t = (3)/(k [A]0)
Q22. If an experimental plot of 1/[A] vs. t gives a slope of 0.02 L mol⁻¹ s⁻¹, what is the rate constant k?
- 0.02 s⁻¹
- 0.02 L mol⁻¹ s⁻¹
- 50 L mol⁻¹ s⁻¹
- 0.02 mol L⁻¹
Correct Answer: 0.02 L mol⁻¹ s⁻¹
Q23. Which scenario would make a bimolecular drug degradation appear first order experimentally?
- Both reactants at identical low concentrations
- Reaction in gas phase only
- One reactant maintained in large excess (pseudo-first-order)
- Using a catalyst
Correct Answer: One reactant maintained in large excess (pseudo-first-order)
Q24. How would you experimentally confirm that a reaction is truly second-order rather than a mixture of orders?
- Measure only one time point
- Fit multiple kinetic models and test linearity of 1/[A] vs. t across concentrations
- Assume second-order from stoichiometry alone
- Use color change as sole evidence
Correct Answer: Fit multiple kinetic models and test linearity of 1/[A] vs. t across concentrations
Q25. Which of the following is a common application of second-order kinetics in pharmaceutical science?
- Zero-order release from matrix tablets only
- Enzyme-catalyzed one-substrate reactions exclusively
- Bimolecular drug–nucleophile degradation and second-order hydrolysis
- Diffusion-limited processes that are always zeroth order
Correct Answer: Bimolecular drug–nucleophile degradation and second-order hydrolysis
Q26. During kinetics analysis, experimental noise causes some scatter. Which method reduces scatter impact for second-order plotting?
- Plot raw concentration vs. t without transformation
- Average replicate measurements and use 1/[A] vs. t linear regression
- Normalize data to arbitrary units only
- Use only the last data point
Correct Answer: Average replicate measurements and use 1/[A] vs. t linear regression
Q27. If rate = k[A][B] and initial rates show a zero-order dependence on B, which conclusion is likely?
- B is in large excess making rate independent of B
- B is absent from the mechanism
- The reaction is third order
Correct Answer: B is in large excess making rate independent of B
Q28. Which replacement of concentration with absorbance is valid for kinetic plotting when Beer–Lambert law holds?
- Use absorbance directly in 1/[A] vs. t without calibration
- Convert absorbance to concentration using A = εlc, then plot 1/[A] vs. t
- Plot ln(absorbance) vs. absorbance
- Absorbance cannot be used for kinetics
Correct Answer: Convert absorbance to concentration using A = εlc, then plot 1/[A] vs. t
Q29. Which of the following kinetic parameters is most useful for comparing degradation rates of two drugs undergoing second-order hydrolysis?
- Initial concentration only
- Rate constant k with proper units
- Color of solution
- Half-life without reporting [A]0
Correct Answer: Rate constant k with proper units
Q30. In a batch experiment you find that doubling both [A]0 and [B]0 increases the initial rate by a factor of four. Which overall order does this indicate?
- Zero order
- First order
- Second order
- Third order
Correct Answer: Second order

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